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Question > if x+1x=1x+\frac{1}{x}=1x+x1=1, solve x2026+1x2026=x^{2026}+\frac{1}{x^{2026}}=x2026+x20261= ? --- Answer From x+1x=1x+\frac1x=1x+x1=1, multiply through by xxx (note x≠0x\neq 0x=0):…
Question > 求解图中的题目 --- Answer 由 m2−5m+1=0m^2-5m+1=0m2−5m+1=0，求 mm2−m+1\dfrac{m}{m^2-m+1}m2−m+1m。 先确定 m≠0m\ne 0m=0：若 m=0m=0m=0，代入原式得 1=01=01=0，矛盾，所以可以放心在分式中约掉 mmm。 变形原式： m2−5m+1=0…m^2-5m+1=0…m2−5m+1=0…